Hooke's Law for Spring
6. Hooke's Law
Hooke's Law states that "if the dance style does not exceed the elastic limit of the spring, then the increase in the length of the spring is directly proportional to the tensile force". Mathematically written as follows.
Information:
F = external force applied (N)
k = spring constant (N / m)
Δx = Increase in spring length from its normal position (m)
Hooke's Law for Spring
6a. Series Arrangement
If two springs that have the same spring constant are arranged in series, then the spring length becomes 2x. Therefore, the spring equation is as follows:
Information:
Ks = Spring Equation
k = spring constant (N / m)
Whereas the equations for n springs whose constants and series are arranged are written as follows.
Information:
n = Number of springs
6b. Parallel Arrangement
If the springs are arranged in parallel, the length of the springs will remain the same as before, while the width of the springs will be more than 2x when the springs are arranged in two pieces. The spring equations for the two springs are arranged in parallel, namely:
Information:
Kp = Spring arrangement parallel arrangement
k = spring constant (N / m)
Whereas the equation for n springs which are the same constants and arranged in parallel, will produce stronger springs because the spring constants become larger. The spring equation can be written as follows.
Information:
n = Number of springs
Examples of Hooke's Legal Questions
A spring has an increase of 0.25 meters in length after applying force. If the spring reads 400 N / m. How much force does this spring have?
known :
x = 0.25 m
k = 400 N / m
asked F ....?
Answer
F = k. x
F = 400 N / m x 0.25 m
F = 100 N
So the force applied to the spring is 100 Newtons.
That is the full review Hopefully what is discussed above is useful for readers. That is all and thank you.